Misplaced Pages

Momentum transfer

Article snapshot taken from Wikipedia with creative commons attribution-sharealike license. Give it a read and then ask your questions in the chat. We can research this topic together.
Process of transferring momentum from one location to another
This article needs additional citations for verification. Please help improve this article by adding citations to reliable sources. Unsourced material may be challenged and removed.
Find sources: "Momentum transfer" – news · newspapers · books · scholar · JSTOR (November 2024) (Learn how and when to remove this message)

In particle physics, wave mechanics, and optics, momentum transfer is the amount of momentum that one particle gives to another particle. It is also called the scattering vector as it describes the transfer of wavevector in wave mechanics.

In the simplest example of scattering of two colliding particles with initial momenta p i 1 , p i 2 {\displaystyle {\vec {p}}_{i1},{\vec {p}}_{i2}} , resulting in final momenta p f 1 , p f 2 {\displaystyle {\vec {p}}_{f1},{\vec {p}}_{f2}} , the momentum transfer is given by

q = p i 1 p f 1 = p f 2 p i 2 {\displaystyle {\vec {q}}={\vec {p}}_{i1}-{\vec {p}}_{f1}={\vec {p}}_{f2}-{\vec {p}}_{i2}}

where the last identity expresses momentum conservation. Momentum transfer is an important quantity because Δ x = / | q | {\displaystyle \Delta x=\hbar /|q|} is a better measure for the typical distance resolution of the reaction than the momenta themselves.

Wave mechanics and optics

A wave has a momentum p = k {\displaystyle p=\hbar k} and is a vectorial quantity. The difference of the momentum of the scattered wave to the incident wave is called momentum transfer. The wave number k is the absolute of the wave vector k = p / {\displaystyle k=p/\hbar } and is related to the wavelength k = 2 π / λ {\displaystyle k=2\pi /\lambda } . Momentum transfer is given in wavenumber units in reciprocal space Q = k f k i {\displaystyle Q=k_{f}-k_{i}}

Diffraction

The momentum transfer plays an important role in the evaluation of neutron, X-ray, and electron diffraction for the investigation of condensed matter. Laue-Bragg diffraction occurs on the atomic crystal lattice, conserves the wave energy and thus is called elastic scattering, where the wave numbers final and incident particles, k f {\displaystyle k_{f}} and k i {\displaystyle k_{i}} , respectively, are equal and just the direction changes by a reciprocal lattice vector G = Q = k f k i {\displaystyle G=Q=k_{f}-k_{i}} with the relation to the lattice spacing G = 2 π / d {\displaystyle G=2\pi /d} . As momentum is conserved, the transfer of momentum occurs to crystal momentum.

The presentation in reciprocal space is generic and does not depend on the type of radiation and wavelength used but only on the sample system, which allows to compare results obtained from many different methods. Some established communities such as powder diffraction employ the diffraction angle 2 θ {\displaystyle 2\theta } as the independent variable, which worked fine in the early years when only a few characteristic wavelengths such as Cu-K α {\displaystyle \alpha } were available. The relationship to Q {\displaystyle Q} -space is

Q = 2 k sin ( θ ) {\displaystyle Q=2k\sin \left(\theta \right)}

with k = 2 π / λ {\displaystyle k={2\pi }/{\lambda }} and basically states that larger 2 θ {\displaystyle 2\theta } corresponds to larger Q {\displaystyle Q} .

See also

References

  1. "Partial-wave analysis of nucleon-nucleon scattering below the pion-production threshold". Physical Review C. arXiv:1304.0895. doi:10.1103/PhysRevC.88.024002.
Categories: